Removing solder circles from removed attachments

[Dan Schultz]

......It would quickly leave only the tinned parts behind. So it seems it should work on a larger scale with a shop vac with a reducer nozzle.

Getting the globs of solder off is the easy problem... just heat and wipe with just about anything. That's what I use those 'pad-savers' that I snitch out of clarinets and saxes for. Even though messing around with a shop-vac might be of some benefit getting globs of solder off, the tinning that's left behind is the difficult part to remove without buffing.

[MartyNeilan]

Heat and wipe, then very lightly sand, then strap with polish. That is it.

Sounds just like potty training!

[SplatterTone]

So, does NO one here use oiled Q-Tips for wiping? I highly recommend them. A shop vacuum? Why?

Every shop has one (right?), fast, can't smear. Sarah Palin uses a shop vac.

[windshieldbug]

Sarah Palin uses a shop vac.

I'm not sure that she does. But she can see one from her backyard.

[windshieldbug]

You can actually see Russia from Alaska...

...which is, actually, true:


The distance between the shown Russian island and the shown Alaskan island is 2.5 miles.

This can be determined in a number of ways but perhaps the easiest is by using Pythagoras theorem of right-angled triangles. Using this, the distance to the horizon is:

SQRT (h+2rh)

Where h is the eye height above sea level and r is the radius of the earth (roundly, 4,000 miles).


Using feet throughout (for a six foot eye height) the calculation becomes:

SQRT (6+(2*21120000*6) = 15920 feet.

Divide this by 5,280 (feet in a mile) and you get 3.01 miles

The principle assumes that the earth is a perfect sphere (which it is not). The calculation is the distance in a straight line from the observer's eye to the horizon and not the distance via the (curved) surface (which would be longer).

SNL, though, was funnier...

[Rick Denney]

...
Using feet throughout (for a six foot eye height) the calculation becomes:

SQRT (6+(2*21120000*6) = 15920 feet.

Divide this by 5,280 (feet in a mile) and you get 3.01 miles

The principle assumes that the earth is a perfect sphere (which it is not). The calculation is the distance in a straight line from the observer's eye to the horizon and not the distance via the (curved) surface (which would be longer).

It also assumes that the terrain of the distant island never rises above zero feet above sea level.

Rick "who can see mountains a heck of lot farther away than 3.01 miles" Denney

[J.c. Sherman]

I'll eat my hat if she's been to that little island and had international relations with the other...

J.c.